Posts Tagged ‘aromatic’

Aromatic electrophilic substitution. A different light on the bromination of benzene.

Wednesday, March 12th, 2014

My previous post related to the aromatic electrophilic substitution of benzene using as electrophile phenyl diazonium chloride. Another prototypical reaction, and again one where benzene is too inactive for the reaction to occur easily, is the catalyst-free bromination of benzene to give bromobenzene and HBr. 

br2+benzenebr2+benzene

The “text-book” mechanism involves nucleophilic attack by the benzene on the bromine to form a “Wheland intermediate” (the blue arrows) followed in a clear second step by proton removal by the liberated bromide anion (the red arrows). But one group had other ideas[1], proposing in 2011 that the blue and red arrows conflate into a single concerted process which does NOT involve an explicit Wheland intermediate ion-pair. The text-books would have to be re-written! Paul Schleyer (a co-author of the above) recently contacted me about this reaction, noting that no explicit intrinsic reaction coordinate (IRC) had been reported in the 2011 article. Could I run one to establish that the course of this reaction really was concerted and “Whelandless“?

The level of theory used before[1] is rb3lyp/6-311++G(2d,2p)/SCRF=CCl4 (the r is added here, for reasons that will soon become apparent) and the animation[2] is shown below, which is followed by repeating the calculation with addition of a D3-type dispersion correction to the core rb3lyp DFT method.[3] Without dispersion, the final HBr becomes H-bonded to the other Br, but with dispersion it instead forms a π-facial hydrogen bond to the aromatic ring. Even for such a small molecule, one can easily observe the effects of dispersion forces!

Br2+benzeneBr2+benzene+D3

br2-d3br2+d3

The reaction is indeed concerted, but it is also asynchronous as revealed by the characteristic feature at IRC ~3. We might conclude that the Wheland does make an appearance in this mechanism, but only as a “hidden intermediate“. It is a relay-race with the blue arrows above running first, and then without pause smoothly passing the baton of the reaction to the red arrows. The activation energy is high, commensurate with a reaction that in fact does not take place at normal temperatures.

Boris Galabov (another co-author[1]) then pointed out to me that the spin-restricted wavefunction (r above) at the transition state is unstable with respect to spin unrestriction.[4] This means that some open-shell biradical character is present at least at the transition state if not the entire pathway. So what would happen if the IRC were repeated using ub3lyp instead of rb3lyp? Would allowing for biradical character still retain the concerted nature?

Before showing the results, I have to point out that the uIRC must be done in two stages, the first being the path to the transition state and the second the path down from it to products (the program I use to show the profiles is not capable has errors when splicing the two together). First the upward path[5] (without dispersion) ending at the TS, followed by the path down.[6]

urE

IRC profile for spin-unrestricted pathway 
ufE
ufG

On the approach path, the spin expectation operator <S2> starts at zero but at IRC ~2.0 it becomes non-zero (biradical character forms) and this persists to the transition state and to IRC ~-2 beyond on the downward path before reverting again to a closed shell singlet. In this central region we have what amounts to a “hidden biradicaloid intermediate”. Since the C-Br bond formation and the subsequent C-H bond cleavage are NOT synchronous, we also retain the hidden Wheland characteristics. So this system is perhaps best described as having a “hidden biradicaloid Wheland intermediate“; a double whammy in the vernacular.  The non zero value of  <S2> lowers the activation barrier from  ~42 kcal/mol to  ~37 kcal/mol, but it still remains a barrier which is insurmountable at room temperatures.

The bottom line remains: according to this quantum model, the reaction is concerted, as originally claimed.[1]


The technical explanation is as follows. The IRC is started at the TS, and the SCF is converged using a broken-symmetry keyword guess(mix). As the IRC proceeds on the path down to reactant, each step uses the density matrix from the previous step as the initial SCF guess. This ensures that the unrestricted wavefunction remains symmetry broken if that is the lowest energy solution. Before the reactant is reached however, <S2> has collapsed to zero. Then the forward path is started, again from the TS. However, the program continues to use the last density matrix and hence <S2> continues to be zero for this entire path. Hence the reason for performing two separate IRC calculations, to ensure that the correct value of <S2> is achieved on both pathways.


References

  1. J. Kong, B. Galabov, G. Koleva, J. Zou, H.F. Schaefer, and P.V.R. Schleyer, "The Inherent Competition between Addition and Substitution Reactions of Br<sub>2</sub> with Benzene and Arenes", Angewandte Chemie International Edition, vol. 50, pp. 6809-6813, 2011. https://doi.org/10.1002/anie.201101852
  2. H.S. Rzepa, "Gaussian Job Archive for C6H6Br2", 2014. https://doi.org/10.6084/m9.figshare.956223
  3. H.S. Rzepa, "Gaussian Job Archive for C6H6Br2", 2014. https://doi.org/10.6084/m9.figshare.956247
  4. M.J. Dewar, S. Olivella, and H.S. Rzepa, "MNDO study of ozone and its decomposition into (O2 + 0)", Chemical Physics Letters, vol. 47, pp. 80-84, 1977. https://doi.org/10.1016/0009-2614(77)85311-6
  5. H.S. Rzepa, "Gaussian Job Archive for C6H6Br2", 2014. https://doi.org/10.6084/m9.figshare.958784
  6. H.S. Rzepa, "Gaussian Job Archive for C6H6Br2", 2014. https://doi.org/10.6084/m9.figshare.958785

Aromatic electrophilic substitution: a different way of predicting regiospecificity

Saturday, April 4th, 2009


Every introductory course or text on aromatic electrophilic substitution contains an explanation along the lines of the resonance diagram shown below. With an o/p directing group such as NH2, it is argued that negative charge accumulates in those positions as a result of the resonance structures shown.

groups1

MEP for PhNH2. Click for 3D.

The opposite occurs for electron withdrawing groups. Shown below is a group such as BR2, a somewhat unusual choice it has to be said (and indeed rather un-represented in the literature as well).

groups2

MEP for PhBH2. Click for 3D.

But stick with me for a little while on this one, since we are now going to pose the question: what the result of combining both groups onto the same aryl ring, as below?

mixed2

MEP for PhBH2NH2. Click for 3D.

The conventional outcome, based on the resonance forms shown in the first two diagrams, is that the two positions annotated with red text are disfavoured, and the two positions labelled with green or orange text are both favoured. Thus far, we are still in “exam question territory”. Reality however intrudes. When a similar combination of electron withdrawing and donating groups is tried out in the lab, only the green outcome is observed, and not the orange. So finally, the point of this blog. Is there any other tool we can use to (correctly) predict the outcome of this particular reaction?

One way of mapping where charge in a molecule accumulates or decreases is a property known as the molecular electrostatic potential (see 10.1021/ja973105j and references cited there for details). Put simply, it measures how attractive (blue) or repulsive (red) any region of the molecule is to a proton placed at any point surrounding the molecule. Mapping these regions produces so-called iso-surfaces, where the measure of repulsion or attraction is the same everywhere on this surface.

So now, if you click on the first diagram, you will see this MEP. Notice how it is blue close to the o or p positions, and does its best to avoid the m position.

Molecular electrostatic potential

Molecular electrostatic potential

Clicking on the second diagram will reveal the opposite.

Molecular electrostatic potential

Molecular electrostatic potential

Thus far this simple picture is in perfect accord with the simple resonance diagrams we started with. But the advantage of this MEP method is that the effects of two (or indeed more) substituents can be properly combined to give an overall effect. Thus in the third diagram, you can now see that the blue accumulates only over the green-text region, and not at all over the orange-text region!

Molecular electrostatic potential

Molecular electrostatic potential

OK, one can derive a resonance structure in 5 seconds in an exam. One can hardly compute a MEP under such conditions. But what this example shows is that sometimes, quantum mechanics produces results which cannot be simply reduced to memorable rules, but must be applied natively to get the correct result.